Question

How many 176ohm resistors in parallel are required to carry 5a on a 220v line?

Answer 1

Answer:

since we know that

$r = \frac{v}{i}$

so total resistance will be

$r = \frac{220}{5}$

i.e r=44ohm(net resistance)

when resistors are connected in parallel then net resistance is

$\frac{1}{r} = \frac{1}{r1} +\frac{1}{r2}$

let n be the numbers of resistors

so $\frac{1}{44} = { \frac{1}{176}}n$

so

$n = \frac{176}{44}$

n=4

therefore 4 resistors each of having 176ohm resistance are required

Answer 2

$\huge\mathfrak\red{Question :- }$

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

$\huge\mathfrak\red{Answer :- }$

➤ voltage= 220V

➤ Current = 5A

➤ Resistance= 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

⇒ n= R'/R = 176/44 = 4

Number of resistors used = 4