Question

how many 176ohm resistors ( in parallel) are required to carry 5A on a 220 v line​

Answer 1

Answer:

n = 4

Step-by-step explanation:

Resistance of 1 resistor = 176 ohm

Let the no. of resistors be n

So, equivalent resistance = 176/n ohm

Current = 5A

Potential Difference = 220V

We know that, V = IR

⇒ 220 = 5 x 176/n

⇒ n = 5 x 176/220

⇒ n = 176/44 = 4

Hope this helps.....

Answer 2

Given :

• Current (I) = 5A
• Voltage (V) = 220 V
• Resistance (R) = 176 ohm

Find out :

• How many resistance required

Solution :

Let " n " be the number of resistance

According to the given condition

→ 1/R = 1/176 + 1/176 ........n/176

→ 1/R = n/176

→ R = 176/n

Now, according to Ohm's law

This law states that ❝ the current flowing through conductor is directly proportional to the potential difference and other physical condition remains the same.❞

→ V = IR

→ 220 = 5 × 176/n

→ 220 = 880/n

→ n = 880/220

→ n = 4

Hence,

• The number of resistance required is 4