Question

How many 176reristersare required to carry 5A current on 220vlines.

Answer 1

For x number of resistors of resistance 176 Ω,

Here Supply voltage, V = 220 V

Current, I = 5 A

Equivalent resistance of the combination = R, given as

I/R=x*[1/176]

R=176/x

From ohm law

V/I=176/x

x=176*I/V

=176*5/220

=4

∴four resistors of 176 Ω are required to draw the given amount of current.

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