Question

how many 2 digit natural numbers are divisible by 6 find solution by arithmetic progression

Answer 1

Answer:

15

Step-by-step explanation:

The First two digit no. Divisible by 6 are 12 and the last two nos. divisible by 6 is 96,

So, let a = 12 , d = 6 , an = 96,

Then,

an=a+(n-1)d

96=12+6n-6

96=6(n+1)

16=n+1

n=15.

Please mark it as brainliest

Answer 2

Answer:

this is correct answer