Math, asked by rpattnaik2013, 9 months ago

how many 2 digit no.s are divisible by 3

Answers

Answered by Joon111
3

First two digit number divisible by 3 = 12

Last two digit number divisible by 3 = 99

An arithmetic progression (A.P) is a progression in which the difference between two consecutive terms is constant.

A.P = 12,15,18,…,99

here

First term (a) = 12

Common difference (d) = 3

Let us consider there are n numbers then

an = 99

a + (n – 1)d = 99

a + (n – 1)d = 9912 + (n – 1)3 = 99

a + (n – 1)d = 9912 + (n – 1)3 = 9912 + 3n – 3 = 99

a + (n – 1)d = 9912 + (n – 1)3 = 9912 + 3n – 3 = 99n = 29+1

n = 30

∴ Two digit numbers divisible by 3 = 30.

Answered by vanshkjain000
2

Answer:

30

Step-by-step explanation:

Here, 12,15,18,21 are in A.P

a = 12

d = 3

an = 99

an = a + (n-1)d      # Formula for nth term of an A.P

99 = 12 + (n-1) 3

99 - 12 = (n-1) 3

87 / 3 = n-1

29 + 1 = n

∴ n = 30.

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