How many 2 digit numbers can you make using the following digits only once in each number ? 2 4 6
Answers
Step-by-step explanation:
Assuming each digit can only be used once, simply use the Permutation formula, which is P(n,k)=n!(n−k)! , where n=4 and k=2 . This is because we are asking how many ordered arrangements of size 2 can be made from 4 possible options. Note that we are looking for permutations rather than combinations since numbers are distinct if the order is different, even if the elements in the number are the same. For example, even though 24 and 42 have the same elements, they are different numbers, and are considered distinct. 24 and 42 represent one combination, but 2 permutations.
Thus, the number of two-digit numbers that can be made with the digits 2, 4, 6, and 8 is:
4!2!
=242
=12
Therefore, 12 two-digit numbers can be made with the digits 2, 4, 6, and 8.
Answer:
fivefivefivefivefive