how many 2-input and and or gates are required to realize y=cd+ef+g
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Answer:
2 And gate and 2 Or gate
Explanation:
Given: cd+ef+g
step 1:First AND Gate ,we will solve cd
i.e:- c.d
step 2:Second AND Gate to solve ef
i.e:- e.f
step 3:First OR gate to add cd+ef ,i.e:-P
step 4:Or gate to solve P+g
∴2 And Gate and 2 OR Gate.
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