Question

how many 2digit no.natural no. are divisibel by 5 with remainder 1​

Answer 1

Answer:

18

Step-by-step explanation:

The two-digit numbers which leave the remainder 1 when divided by 5 are ;

11,16,21,26,.......86,91,96

In this A.P :

a = 11

d = 16-11 = 5

l = 96

n = ?

Tn = a+(n-1)d

96 = 11+(n-1)5

n-1 = 85/5

n = 17+1

n = 18

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