Question

how many 2m naoh solution is mixed with 400 ml of 3m naoh solution to prepare 2.5m naoh solution​

Answer 1

Answer:

Molarity= n V (solution)

M₁

n

V₁(solution)

n

M₂ V₂(solution) ...(2)

From (1) and (2)

M₁ M₂ V₂ V₁

substituting the values,

V₂ 2M x 100ml 0.5M -

V₂ = 400ml

Hence, V₂ - V₁ = 400ml - 100ml = 300ml

Therefore, 300ml of water is added to the solution.

Answer 2

Answer:

answer is 300ml

Explanation:

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