How many 3/4kg packets can be made from 37/2 kg of tea, and how much tea would remain
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Answer:
Mass of Water = 2000g
If he had water,
Required heat = msΔT =2000×1×(100−0)=200000calories
If he had ice,
Required Heat = Heat to melt Ice(mL) + Heat to raise temperature from 0
o
C to 100
o
C (msΔT)
Required heat =(2000×80)+(2000×1×(100−0))=160000+200000=360000calories
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