Question

How many 3 digit even positive numbers can be formef from the digit 0to9 if the gigits can be repeated?
I am surely give mark as brainly.​

Answer 1

500 is correct answer.

Answer 2

the first one 100 = a(first term)

last one is 998= tn(last term)

d=2 ( difference in digits)

n=? (number of terms)

tn= a+(n-1)d ( ap formula )

998=100(n-1)2

898/2=n-1

449+1=n

500=n

500 hundred three digit number can be formed