Question

How many 3 digit natural numbers are divisible by 8 ?

Answer 1

three digits natural no. divisible by 8 are 104,112.....992 which form of an A.P in which a=104 , d = t2-t1 = 112-104 =8 , tn= 992
tn= a+(n-1)d
992 = 104+ (n-1)8
992-104= (n-1)8
888/8=(n-1)
111=(n-1)
n=111+1
n=112

Answer 2

Answer:

112

Step-by-step explanation:

The formula to find the numbers of terms in an arithmetic sequence is given by

n = [(l - a) / d] + 1

Substitute a = 104, l = 992 and d = 8.

n = [(992 - 104) / 8] + 1

n = [888/8] + 1

n = 111 + 1

n = 112

So, number of 3 digit numbers divisible by 8 is 112.