how many 3 digit natural numbers are there which leave the remainder 3 when divided by 5
Answers
Answered by
0
Answer:
Therefore, we have 180 3-digit natural numbers that leave a remainder of 3 when divided by 5. The first number is 103 and the last number is 998. 179 + 1 ==180 such 3-digit numbers. Hence n =180 so there will be 180 three digit natural numbers.
Answered by
6
- 248
- 348
- 448
are the three digit number
Similar questions