How many 3 digit no are there between 100 and 1000 having exactly one 7?
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994= a+(n-1)d
994= 105+(n-1)7
994-105=(n-1)7
889/7 =(n-1)
127+1=n
n = 128
128 terms are there
994= 105+(n-1)7
994-105=(n-1)7
889/7 =(n-1)
127+1=n
n = 128
128 terms are there
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