Question

How many 3-digit number can be formed without using digits 1, 2, 3, 9, 5 if repetition of

digits is not allowed ? ​

Answer 1

Answer:

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Answer 2

Answer:

64

Step-by-step explanation:

We have to consider 1-digit numbers, 2-digit numbers, 3-digit numbers and 4-digit numbers.

Here we are given four digits 1, 2, 3 and 9; repetition of digits not allowed.

Number of 1-digit numbers = 4.

Let us consider 2-digit numbers. The first place (ten's place) can be filled in 4 ways,then second place (unit's place) can be filled in 3 ways. Therefore, number of 2-digit numbers

= 4x 3=12.

Similarly, number of 3-digit numbers 4 x 3 x 2 =24.

The number of 4-digit numbers =4 x3 x 2 x 1 24.

Hence, the required number of numbers = 4 + 12 + 24 + 24= 64.