Question

How many 3- digit numbers are divisible by 3????

Answer 1

$\textbf{To find:}$

$\text{How many 3- digit numbers are divisible by 3}$

$\textbf{Solution:}$

$\text{The first 3 digit number divisible by 3 is 102}$

$\text{The last 3 digit number divisible by 3 is 999}$

$\text{Thus, we an A.P}$

$102,\,105,\,108,...............,\,999$

$\text{Here,}\,a=102,\;d=3,\;l=999$

$\textbf{Number of terms in the A.P}$

$\bf=\dfrac{l-a}{d}+1$

$=\dfrac{999-102}{3}+1$

$=\dfrac{897}{3}+1$

$=299+1$

$=300$

$\textbf{Answer:}$

$\textbf{There are 300 three digit numbers are divisible by 3}$

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Answer 2

Step-by-step explanation:

The three digit natural numbers start from 100 and ends with 999.

The first three digit number which is divisible by 3 is 102.

The last three digit number which is divisible by 3 is 999.

The number of three digit numbers divisible by 3 are 3999−3102+1=333−34+1=300.