How many 3-digit numbers are possible using 6,5,4,3,2,1
vishruthpreddy:
90
Answers
Answered by
1
Total no =6
So 6C3= 6x5x4x3x2x1/3x2x1 = 6x5x4 = 120 answer
Answered by
1
they can be arranged in
1st digit in 6 ways
2nd digit in 5 ways
3rd digit in 4 ways
so total number of ways are
6*5*4=
30*4=120
120 ways
1st digit in 6 ways
2nd digit in 5 ways
3rd digit in 4 ways
so total number of ways are
6*5*4=
30*4=120
120 ways
Similar questions