Question

how many 3 digit numbers are there which leave a remainder 3 divisible by 7​

Answer 1

all the numbers between 100 and 999 which are divisible by 7 and leaves the remainder 3 are in AP, where, Hence, there are 129 numbers between 100 and 999 which are exactly divisible by 7 and leaves the remainder 3.


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Answer 2

Answer:

first 3 digit no. divisible by 7 is 105 it leaves a remainder 3.so the 3 digit no. is 108.similarly the last 3 digit no. is 997. Now

n={(997-108)/7}+1

n=128