how many 3 digit numbers are there. which leaves remainder 1 on division by 5
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Answer:
smallest 3 digit no. which leaves remainder 1 on division by 5 is =100
Largest 3 digit no. which leaves remainder 1 on division by 5 is =997
Now, we can observe that it is forming an AP with
first element = 100
last element =997
common difference =3
let an=a+(n-1)d
so,
997 = 100 + (n-1)3
997 - 100 = 3n -3
897 + 3 = 3n
900 = 3n
900/3 = n
n = 300
Therefore, there are 300, 3-digit number which leaves remainder 1 on division by 5.
Answered by
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Answer:
largest 3-digit number which leave 1 as a remainder when divided by 5 is 996
smallest 3-digit number which leave 1 as a remainder when divided by 5 is 101
common difference is 5
tn=a+(n-1)d
996=101+(n-1)5
996=101+5n-5
996=96+5n
5n=996-96
5n=900
n=180
Total 180, 3-digit numbers leave 1 as a remainder when divided by 5
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