Math, asked by CruddyGamer, 3 months ago

How many 3-Digit numbers can be formed by placing digits 2, 3, 4, 5, 6? tell the numbers

Answers

Answered by hrn21agmailcom

1

Answer:

20

Step-by-step explanation:

given digits : 2, 3, 4, 5, 6

total digits : 5

the number : three digited

permutations = nPr

since....

n = 5 & r = 3

nPr = 5P3 = 5! / 3!

nPr = 20

hence...

the three digited numbers are : 20

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