How many 3-Digit numbers can be formed by placing digits 2, 3, 4, 5, 6? tell the numbers
Answers
Answered by
1
Answer:
20
Step-by-step explanation:
given digits : 2, 3, 4, 5, 6
total digits : 5
the number : three digited
permutations = nPr
since....
n = 5 & r = 3
nPr = 5P3 = 5! / 3!
nPr = 20
hence...
the three digited numbers are : 20
Similar questions