How many 3-digit numbers can be formed by using the digits 0,2,3,6,8 when the digits may be repeated any number of times?
Answers
Answer
4 x 5 x 5 =100ways
Solution
The three digits number is formed by using 0,2,3,6 and 8
First digits cannot be 0. So the first digit must be 2, or 3 or 6 or 8. so there are 4 possibilities. the second digit can be selected from any of 5 digits,and third digits also can be selected any of the given 5 digits
So the final result is that ,The three digits number is formed using these numbers =4 x 5 x 5 =100
First digit (Hundreds place) cannot be zero
⇒ Choices are {2, 3, 6, 8} ⇒ 4 choices
Second digit (tens place) can be any of the digits (repeats allow)
⇒ Choices are {0, 2, 3, 6, 8} ⇒ 5 choices
thirds digit (ones place) can be any of the digits (repeats allow)
⇒ Choices are {0, 2, 3, 6, 8} ⇒ 5 choices
Number of ways = 4 x 5 x 5 = 100 ways
Answer: 100 ways