Question

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which
are divisible by 5 and none of the digits is repeated ?​

Answer 1

Answer:

hey friend...here is your answer..

Step-by-step explanation:

the possible numbers can bee..

235

325

675

765

635

625

975

925

935

265

275

295

365

375

395

696

725

735

795

965

these maybe the possible numbers ...

hoping that this answer is helpful...Mark as brainliest if you find soo...

Answer 2

since each desired number is divisible by 5 , so, we must have 5 at the unit place,so, there is 1 way of doing

The tens place can now be filled by any of the remaining digits (2,3,6,7,9,) so, there are 5 ways of filling the tens place

the hundreds place can now be filled by any of the remaining 4 digits , so, there are 4 ways of filling it

therefore , required number of numbers (1×5×4) =20