how many 3 digit numbers can be made from the numbers 1 2 3 4 5 6 7 if repetition is not allowed
PriyeshArya:
Here, order matters... for example 123 and 213 are the two different numbers.. Therefore, there will be a many 3 digits numbers as there are permutations of 7 different digits taken 3 at a time.
Oh ok...
Therefore, the required 3 digit numbers = 7!/(7-3)! = 7×6×5 = 210
therefore, 210 three digit numbers can be formed by using digits from 1 to 7 if repetition of digits is not allowed.
remember here 7! = 7×6×5×4×3×2×1. And 4! = 4×3×2×1....
you can use this in other questions also where repetition of digits is not allowed... Gud Luck.
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2
14 i think so...... This maybe the answer
In ask for details option
Wait a min..... Which class question is this????
I am in 8th standard.......
12th
sorry 11th
Wow!!!!!
Oh sorry... I'm in standard 8
You are in 8th standard???!!!
Yes
Answer is Given in Comment Section of The Question... You can get there by clicking on the top right corner of the main screen of the Question.
Answered by
0
I think it's 21 numbers...
Hope it helps!
Hope it helps!
its Wrong...
Read the chapter Permutations and Combinations
U should ask the questioner to read the chapter!!!! Not him
buddy
questioner is the one who needs correct answer...
i am posting its Answer on The Comment section of the Question .... its option is in top right corner...
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