How many 3-digit numbers can you form by using the digits 2,8,5 only once?
Answers
Answered by
0
Answer:
6
Step-by-step explanation:
a. 285
b. 258
c. 528
d. 582
e. 852
f. 825
Answered by
1
Using fundamental principal of counting
The hundred place can be filled by any one of 3 digits in 3 ways.
The tens place can be filled by remaining 2 digits in 2 ways.
The ones place can be filled by remaining one digit by 1 way only.
So total number of 3 digit number can be formed without repetition of the digit = 3 x 2 x 1 = 6 ways
The hundred place can be filled by any one of 3 digits in 3 ways.
The tens place can be filled by remaining 2 digits in 2 ways.
The ones place can be filled by remaining one digit by 1 way only.
So total number of 3 digit number can be formed without repetition of the digit = 3 x 2 x 1 = 6 ways
Similar questions
Computer Science,
2 months ago
Environmental Sciences,
2 months ago
Math,
2 months ago
Math,
5 months ago
History,
10 months ago