Math, asked by shravani623, 6 months ago

How many 3 digit numbers ending with 7 can be formed from the digits 1, 2, 5, 7, 8 such that digit doesn't repear

Answers

Answered by shubhamgoyal75
0

Answer:

12

Step-by-step explanation:

_ _ 7

first two places can filled by 1, 2, 5, 8.

But a digit can not reappear.

Hundred'th place can filled by using 4 digits and Ten'th place can be filled by 3 digits.

Therefore number of 3 digit numbers ending with 7 are :-

= 4 × 3

= 12

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