Question

how many 3 digit numbers leave remainder 2 when divided by 15​

Answer 1

Hola mate I try it ...

largest 3 digit no. is 999

smallest 3 digit ni. is 100

subtracting,

=》 899

now subtract 2
=》897

divide by 15

=》60 (approx)

so, there are about 60 numbers.

Hope it is right.....

Answer 2

Answer:

60

Step-by-step explanation:

First 3 digit no divible by 15 is 105

If remainder is 2 then no=105+2=107

and last 3 digit no leaving remainder 2 when divided by 15​=992

so the no are

107,122,137....................992

This is an AP

a=107,d=122-107=22,L=992 n=?

L=a+(n-1)d

992=107+(n-1)*15

(n-1)*15=992-107=885

n-1=885/15=59

n=59+1

=60

Hence 3 digit numbers leaving remainder 2 when divided by 15 ​are: 60