Question

How many 3-digit numbers will be there which are divisible by 19?

Answer 1

there should be 3 digit number,So First Digit=114 Last digit which is divisible by 19 is 19*52=988 Apply the formula of A.P....An=a+(n-1)d---------------Eq(1) Where An=988, a=114, common difference d= 19 Applying above value in Eq(1) we get, 988=114+(n-1)19 874=19n-19 893=19n n=893/19 n=47