how many 3- digit odd numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?
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2
123
125
133
135
143
145
153
155
323
325
333
335
343
345
353
355
, 523
525
533
535
543
545
553
555
125
133
135
143
145
153
155
323
325
333
335
343
345
353
355
, 523
525
533
535
543
545
553
555
pandeysatyam57227:
bhai ache se solve kar ke bataiye
There are three possibilities for the last digit: 1,3, and 5. As the final number needs to be odd, only those three numbers are allowed in the last digitThere are seven possibilities for the second digit - any of the digits 0…6 can be usedThere are six possibilities for the first digit - all but ‘0’ can be used.
So the answer is 3×7×6=126
So the answer is 3×7×6=126
Bhai thoda hard h smj jayaga n
hmmm
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