How many 3-digit positive integers are odd and do not contain the digit 5?
Answers
Answered by
0
Unit digit -1,3,7,9
Tenth digit -0,1,2,3,4,6,7,8,9
100th digit -0,1,2,3,4,6,7,8,9
The total possible ways =4*9*9=324
Since in the unit digit there are 4 integers, there exist 9*4=36 redundant 3 digits integer.
therefore 324-36=288 different 3 digit integer is the answer.
Similar questions