How many 3-digits even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?
Answers
━━━━━━━━━━━━━━━━━━━━━━━━━
How many 3-digits even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?
━━━━━━━━━━━━━━━━━━━━━━━━━
━━━━━━━━━━━━━━━━━━━━━━━━━
_______________________________________
➡️Let the 3-digit number be ABC, where C is at the unit’s place, B at the tens place and A at the hundreds place.
➡️As the number has to even, the digits possible at C are 2 or 4 or 6.
➡️That is number of possible digits at C is 3.
➡️Now, as the repetition is allowed, the digits possible at B is 6.
➡️Similarly, at A, also, the number of digits possible is 6.
➡️Therefore,
➡️ The total number possible 3 digit numbers = 6 × 6 × 3 = 108.
━━━━━━━━━━━━━━━━━━━━━━━━━
Answer:
➡️Let the 3-digit number be ABC, where C is at the unit’s place, B at the tens place and A at the hundreds place.
➡️As the number has to even, the digits possible at C are 2 or 4 or 6.
➡️That is number of possible digits at C is 3.
➡️Now, as the repetition is allowed, the digits possible at B is 6.
➡️Similarly, at A, also, the number of digits possible is 6.
➡️Therefore,
➡️ The total number possible 3 digit numbers = 6 × 6 × 3 = 108.
Step-by-step explanation: