how many 3 digits no:s such that when we divided by 7 leave a remainder 3 in each case
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The least three digit number divided by 7 = 105 as we need 3 as reminder add 3 to 105 = 108
now the highest three digit number divided by 7 is 994 as we need 3 as reminder add 3 to 994 = 997
formula:
108+(n-1)7 = 997
= 997 - 108= (n-1)7
= 889÷7=n-1
= n-1 = 127
= n= 128
adhwaithharisree916:
superb answer
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