How many 3 digits number are divisible by 87
Answers
Answered by
29
hello...
lowest 3 digit no. = 174 (87 × 2)
highest 3 digit no = 957 (87 × 11)
a= 174 , d = 87 and last term 957
We've to use last term formula
957 = 174+ ( n -1)×87
957= 174 + 87n - 87
957= 87 + 87n
957-87 = 87n
870 = 87n
n = 10th term
lowest 3 digit no. = 174 (87 × 2)
highest 3 digit no = 957 (87 × 11)
a= 174 , d = 87 and last term 957
We've to use last term formula
957 = 174+ ( n -1)×87
957= 174 + 87n - 87
957= 87 + 87n
957-87 = 87n
870 = 87n
n = 10th term
savi123:
hi
Answered by
5
a=174
d=87
an=9357
an=a+(n-1)d
957=174+(n-1)87
957-174=87n-87
783+87=87n
870=87n
n=10
d=87
an=9357
an=a+(n-1)d
957=174+(n-1)87
957-174=87n-87
783+87=87n
870=87n
n=10
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