How many 3 digits number are there such that their digits are in arithmatic progression with positive difference?
Answers
Answer:
ANSWER
The only three digit numbers with all different digits whose digits are
in GP that we can subtract 400 from and get a positive number
are:
421,842,931
421−400=21, not a three-digit number, so 421 is out
842−400=442, 4,4,2 are not in AP, so 842 is out
931−400=531, 5,3,1 are in AP with common difference -2.
So the number is 931
Step-by-step explanation:
total 16 , 3 Digits numbers are possible where Digits are in AP with +ve differences
Step-by-step explanation:
3 Digits numbers such that their digits are in AP with positive difference
We can fins these number manually as Smallest Digit is 1 & largest Digit is 9 so maximum common difference = 4
Lets check all numbers
123 , 135 , 147 , 159
234 , 246 , 258
345 , 357 , 369
456 , 468
567 , 579
678
789
total 16 , 3 Digits numbers are possible where Digits are in AP with +ve differences
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