how many 330 ohm resistance in parallel are required to carry 20 ampere and 220 volt
Answers
Answer:
Explanation:
220N/330 = 220/11
The common term 220 cancels
N/330 = 1/11
N=330/11 the number of resistors required is 30
30 , resistors of 330 ohm resistance in parallel are required to carry 20 ampere and 220 volt
Explanation:
All resistance are in parallel and equal in values
hence current flowing through each resistance would be equal
Using I = V/R
Current flowing through 1 resistor = 220/330 = 2/3 A
Total Current = 20 A
Number of resistors = (20)/(2/3) = 30
30 Resistors in Parallel
Other way let say there are n resistors in parallel
then 1/ Req = 1/330 + 1/330 +.......................+ n time
=> 1/Req = n/330
=> Req = 330/n
I = V/Req
=> 20 = 220/(330/n)
=> 20 = 2n/3
=> n = 30
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