how many 3digit natural number are divisible by 7 [number system]
Answers
Answer:
first 3-digit number which is divisible by 7 is 105
The last 3-digit number which is divisible by 7 is 994
The list of 3-digit numbers divisible by 7 are
105, 112, 119,…..994 which forms an A.P
Consider a formula
T(n) = a + (n – 1)d
Where
a = 105
d = 7
T(n) = 994
994 = 105 + (n – 1)7
889 = 7n – 7
7n = 896
n = 128
∴ There are 128 3-digits number which are divisible by 7.
Step-by-step explanation:
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Answer:
there are 128 natural numbers which are divisible by 3
Step-by-step explanation:
The first 3-digit number which is divisible by 7 is 105
The last 3-digit number which is divisible by 7 is 994
The list of 3-digit numbers divisible by 7 are
105, 112, 119,…..994 which forms an A.P
Consider a formula
T(n) = a + (n – 1)d
Where
a = 105
d = 7
T(n) = 994
994 = 105 + (n – 1)7
889 = 7n – 7
7n = 896
n = 128
∴ There are 128 3-digits number which are divisible by 7.(please follow me and thank me)