Question

How many 4-digit multiples of 5 can be formed with the digits 5, 3, 2, and 1?

Answer 1

Answer:

If no repetition is allowed then 24 nos can be formed. First X will have 3 options, and second X will have 2 options. So, 6 nos of each type so total 24 nos

Answer 2

Answer:

4-digit multiples of 5 that can be formed with the digits 5, 3, 2, and 1, with repetition are 27 and without repetition are 6.

Step-by-step explanation:

Since we have to form a multiple of 5, the last digit should be either 5 or 0.

We have the digits 5, 3, 2 and 1.

So, the last digit should be fixed that is 5.

Now, we have 2 cases:

If the repetition is allowed, then the numbers formed will be:

3 × 3 × 3 = 27 numbers.

If the repetition is not allowed then the numbers formed will be:

3 × 2 × 1 = 6 numbers.

Therefore, with repetition, the numbers formed are 27 and without repetition the numbers formed are 6.

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