How many 4-digit numbers can be formed from the digits 2, 3, 5, 0, 6, 8, 7 and 9, which are divisible by 2 and none of the digits is repeated? A) 720 b) 750 c) 840 d) 810
Answers
Answered by
0
Answer:
they are 3562,9700,5092
Step-by-step explanation:
it is because when in the last there is even no. then it is divisible by 2
Answered by
1
Answer:
(7×6×5×1)+(6×6×5×3)
=210+540
=750
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