Question

How many 4-digit numbers can be formed using the digits - 0,1,2,3,4 without the repetition of any digit?

Answer 1

Answer:

4×4×3×2=96

Each of these 96 numbers are equally likely & mutually exclusive of each other.

Now, A number is divisible by 4, if last two digits of the number is divisible by 4

Hence we can have the following numbers in the last digit

0

4:

first two places can be filled in 3×2=6 ways

1

2:

first two places can be filled in 2×2=4 ways

2

0:

6 ways

2

4:

4 ways

3

2:

4 ways

4

0:

6 ways

Total number of ways=6+4+6+4+4+6=30 ways

probability=

Totaloutcomes

favorableoutcomes

=

96

30

=

16

5

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