How many 4 digit numbers divisible by 5 can be formed with the digitd 0 1 2 3 4 5 6?
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As the number should be divisible by 5 the last number should be 5 or 0 and now apply permutations ;
the possible first digits : 1,2,3,4,5 total = 5
the possible second digits : 0,1,2,3,4,5 total = 6
the possible third digits : 0,1,2,3,4,5 total = 6
possible fourth digits : 0 and 5 total = 2
Now total possible four digit numbers is
5*6*6*2 = 360
That is the answer ! hope you understand !
the possible first digits : 1,2,3,4,5 total = 5
the possible second digits : 0,1,2,3,4,5 total = 6
the possible third digits : 0,1,2,3,4,5 total = 6
possible fourth digits : 0 and 5 total = 2
Now total possible four digit numbers is
5*6*6*2 = 360
That is the answer ! hope you understand !
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