Math, asked by nonisinghal1, 3 months ago

How many 4's are there in the following arrangement each of which is immediately preceded by an even number but not immediately followed by 6? 2 4 2 E D Q 3 9 2 4 7 M 6 6 T 6 4 1 N 8 4 6​

Answers

Answered by manjulatiwari7312
0

Answer:

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Step-by-step explanation:

otal number of 4's = 13

The 4's in the arrangement are:

437 : There is no pair of numbers preceding ⇒ not eligible

78445 : 7×8>4×5⇒ eligible

84456 : 8×4>5×6⇒ eligible

56432 : 5×6>3×2⇒ eligible

32417 : 3×2<1×7⇒ not eligible

17445 : 1×7<4×5⇒ not eligible

74452 : 7×4>5×2⇒ eligible

21468 : 2×1<6×8⇒ not eligible

89489 : 8×9=8×9⇒ not eligible

89478 : 8×9>7×8⇒ eligible

86425 : 8×6>2×5⇒ eligible

25446 : 2×5<4×6⇒ not eligible

54462 : 5×4>6×2⇒ eligible

∴  Number of 4's satisfying the given criteria = 7.

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