Question

How many 440ohm resistors (in parallel) are required to carry 5ampere in 220volt line?

Answer 1

Answer: You need 5A current over 220V voltage difference. So the total resistance of the circuit in between would be R=V/I, here R=220V/5A=44 Ohm .Now, you have only 440Ohm resistors which are to be connected in parallel only. Let 'n' is the number of 440 Ohm resistors connected in parallel to achieve overall 44 Ohm resistance.Using the formula of equivalent resistance for resistors connected in parallel we get n/440 = 1/44 [(1/R)=(1/R1)+(1/R2)+.... ; R is equivalent resistance, Ri is the resistance of i-th resistor in parallel]So clearly n=10You need ten(10) 440 Ohm resistors in parallel in order to get total 5A current in 220V voltage difference         pls mark as brainliest

Explanation:

Answer 2

$\huge\mathfrak\red{Question :- }$

How many 176 ohm resistors ( in parallel ) are required to carry 5 A on a 220 V line?

$\huge\mathfrak\red{Answer :- }$

➤ voltage= 220V

➤ Current = 5A

➤ Resistance= 44ohm

➤ Resistance of 44ohm is required

if we have same resistors is

⇒ R = R'/n

where n is number of resistor used

Here R '= 176 ohm and R is 44 ohm

⇒ n= R'/R = 440/44 = 10

Number of resistors used = 10