How many 5 digit numbers are there that do not contain 3 or 6?
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as it does not contain 3 or 6. so their will be 8types(0,1,2,4,5,7,8,9) in per digit.
so if it contain 5 digit so the number will be 8^5.but if 0 in first of 5 digit so the
number 7×8^3,7×8^2,7×8,7and 00000 will not be 5 digit numbers.
so the answer is 8^5-7×[8^3+8^2+8+1]-1=
28672.
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