Question

How many 5 digit numbers which are divisible by 5 that can be formed using
the digits 0 to 6. such that no digit occurs more than once
in any number?​

Answer 1

Answer:

624

Step-by-step explanation:

Last two digits must be

( 04,12,16,20,24,32,36 , 40, 52, 56, 60 , 64 )

in order to be from ( 0 - 6 ) be divisible by 4 and not be repeated.

4 cases where 0 is in last 2 digits ( 04,20,40,60 ) the other 3 digits filled by

4 ( 5 x 4 x 3 ) choices = 240

8 ways that don’t use 0 and since 0 can’t be the first digit

( 12 , 16, 24, 32, 36, 52, 56, 64 )

8 ( 4 x 4 x 3 ) = 384

240 + 384 = 624

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