How many 5-digit telephone numbers can be constructed using the digits 0 to 9 if each number starts with 67 and no digit appears more than once?
(Class 11 - Permutations and Combinations)
Answers
Answered by
4
Answer:
336 ways
Step-by-step explanation:
5 digit telephone number has first two nos fixed as 6 and 7.
Out of 10 digits, 2 are fixed and no repetition is allowed.
Now 8 digits in 3 ways can be taken in 8P3 ways
N = 8!/(8-3)!
N = 8!/5!N = 8x7x6 = 336 ways
Answered by
2
Answer:
Your answer is 336 ways...
Step-by-step explanation:
8P3 ways...
8!/(8-3)!
8*7*6=336
Hey, I am also is 11th can u please inbox me
...We can be frnds...if u agree pls inbox me if no give a thanks on this answer☺️
Similar questions