Question

How many 5’s are there in the following sequence such that the sum of the two immediately following digits is greater than the sum of the two immediately preceding digits?
3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4
please explain me this question and the answer .​

Answer 1

Answer:

4 5's are there

Step-by-step explanation:

6+5<5+8 - (1)

5+4<5+5 - (2)

5+5>5+4 - (no count)

5+1<5+3 - (3)

5+7<5+9 - (4)

Answer 2

Answer:

3 5's are there in the sequence.