How many 6 digit no. can be possible which
can not be divisible by 9 if first and
fifth
digit is 5 and 4
Answers
Answer:
I'm sorry but I donno the answer to this.
Is there any other question?
Answer:
How many such 6-digit numbers are possible that cannot be divided by 9 and whose first number is 5 and the third number is 4?
We are looking for 6 Digit Numbers that are not divisible by 9 with the starting Digit and the 3rd Digit being fixed at 5 and 4 respectively.
To do this, let’s first find out as to how many 6 Digit numbers are there having the starting Digit as 5 and 3rd Digit as 4. With 1st and 3rd Digits fixed, the other 4 Digits could be chosen in 10 different ways each and thus we can have 1*10*1*10*10*10 = 10000 different numbers meeting the required criteria.
We know that, with uniform distribution, for every 9 numbers, 8 are not divisible by 9 and 1 is divisible by 9. Considering that there would be uniform distribution for the 10000 numbers in question, there would be 10000*8/9 numbers that would not be divisible by 9.
This is nothing but
80000/9 = 8888.8888…
Now, the question is, whether we should round it to 8889 or keep it at 8888. If we see the very first number as per the required conditions, the number is 504000 and this number is divisible by 9 and therefore, I will not convert 8888.8888… to 8889 but keep it at 8888.
Thus, the required count is 8888.
P. S.: This has been verified with the help of a computer program and indeed the count stands at 8888.