how many 6 digit number be can be formed by the digits 2,3,4,5,6,8when (1) all the numbers are divisible by 2
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We have to form 6 digit telephone number and first two places are fixed with 35,so we have 10-2 =8 digits {0,1,2,…,9 minus 3 and 5} for 4 remaining places.
It can be done in 8P4 =8×7×6×5=56×30
=1680 ways.
Hence total such telephone numbers=1680.
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