How many 6 digit numbers can be formed by using the digits 0 , 1 , 1 , 2 , 2 , 2 ? *
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There are two possible orders for 1 and 2 , and 5 possible places you can put them, then you need to fill the 4 remaining positions using the 7 remaining digits. The digits are all non-zero: Choose 6 symbols from {1,2,3,4,5,6,7,8,9} and permute them: (96)⋅6! =60480.
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