Question

how many 6 digit numbers divisible by 2 can be formed by the first six whole numbers with repetition allowed?

Answer 1

2,4,6 is your answer bro

Answer 2

Given,

The first six whole numbers; 0,1,2,3,4 and 5

To find,

The total number of 6 digit numbers divisible by 2 that can be formed by the given set of numbers, with repetition allowed.

Solution,

We can simply solve this mathematical problem using the following process:

According to the question,

The set of possible digits in the unit place of the favorable 6-digit numbers divisible by 2 = {0,2,4}

Now,

Total number of favorable 6 digit numbers ending with 0

= total number of favorable 6 digit numbers ending with 2

= total number of favorable 6 digit numbers ending with 4

= (number of possible digits in the first place) x (number of possible second digits in the second place) x (number of possible second digits in the third place) x (number of possible second digits in the fourth place) x (number of possible second digits in the fifth place) x (number of possible second digits in the sixth place)

= 5x6x6x6x6x1

{number of possible digits in the first place is 5 since 0 cannot be in the first place to make it a 6-digit number}

So, the total number of 6 digit numbers divisible by 2 that can be formed by the given set of numbers, with repetition allowed

= (5x6x6x6x6x1) x 3

= 19,440

Hence, a total of 19,440 6-digit numbers, divisible by 2, can be formed by the given set of numbers, with repetition allowed.