Question

How many 7060 ohm resistor in parallel are required to 5 ampere on a 16 volt

Answer 1

Answer:

QUESTION:

How many 7060 ohm resistor in parallel are required to 5 ampere on a 16 volt.

GIVEN:

• resistance of one resistor , r=7060 ohm

• current, I = 5 ampere

• potential difference , V = 16 volt

TO FIND:

number of resistors connected in parallel, n

FORMULA:

if n resistors of equal resistance are connected in parallel, then the resultant resistance will be,

R=r/n

where,

• R is the net resistance
• r is the individual resistance
• n is the number of resistors.

according to OHM'S LAW,

V=IR

SOLUTION:

STEP 1:

TO FIND THE NET RESISTANCE:

R=r/n

R=7060/n

STEP 2:

APPLY OHM'S LAW:

V=IR

$16 = 5 \times \frac{7060}{n} \\ \\ \frac{16}{5} = \frac{7060}{n } \\ \\ \frac{5}{16} = \frac{n}{7060} \\ \\ n = 7060 \times \frac{5}{16} \\ \\ n = 441.25 \times5 \\ \\ n =2206.25$

ANSWER:

therefore 2206.25 resistors are connected in parallel.

since the number of resistors can not be in decimal, the above combination is not possible practically

Answer 2

Given :

▪️Resistance, r = 7060 ohm

▪️Potential difference, v = 16 volt

▪️Current, I = 5 Ampere

To find :

The number of resistors connected parallel in a circuit, n = ?

Formula :

R = $\frac {r}{a}$

Here,

R → Net resistance

r → Individual resistance

n → Number of resistors.

Solution :

Using ohm’s law,

$\boxed{V \: = \: IR}$

Net resistance, $R = \frac{r}{n}$

→ $R = \frac {7060}{n}$

→ $\frac {16}{5} = \frac {7060}{n}$

→ $\frac {7060}{n} = \frac {5}{16}$

→ $\frac {5}{16} = \frac {n}{7060}$

→ $n \: = \: 441.25×5$

→ $n \: = \: 2206.25$

$\therefore$ The number of resistors connected parallel are 2206.25.